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1z0-071 PDF DEMO:

QUESTION NO: 1
Which two statements are true regarding the COUNT function?
A. The COUNT function can be used only for CHAR, VARCHAR2, and NUMBER data types.
B. COUNT (*) returns the number of rows including duplicate rows and rows containing NULL value in any of the columns.
C. COUNT (cust_id) returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_ID column.
D. COUNT (DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and
NULL values in the INV_AMT column.
E. A SELECT statement using the COUNT function with a DISTINCT keyword cannot have a WHERE clause.
Answer: B,D

QUESTION NO: 2
Examine the commands used to create DEPARTMENT_DETAILS and
COURSE_DETAILS:
You want to generate a report that shows all course IDs irrespective of whether they have corresponding department IDs or not but no department IDs if they do not have any courses.
Which SQL statement must you use?
A. SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN department_details d ON (c.department_id<>d. department_id)
B. SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN department_details d ON (c.department_id=d. department_id)
C. SELECT c.course_id, d.department_id FROM course_details c RIGHT OUTER JOIN
.department_details d ON (c.depatrment_id=d.department_id)
D. SELECT course_id, department_id, FROM department_details d RIGHT OUTER JOIN course_details c USING (department_id)
Answer: B

QUESTION NO: 3
View the exhibit and examine the structure of the STORES table.
STORES table
NameNull?Type
---------------------- -------------
STORE_IDNUMBER
NAMEVARCHAR2(100)
ADDRESSVARCHAR2(200)
CITYVARCHAR2(100)
COUNTRYVARCHAR2(100)
START_DATEDATE
END_DATEDATE
PROPERTY_PRICENUMBER
You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATE in the range of 36 months starting from 01- Jan-2000 and above.
Which SQL statement would get the desired output?
A. SELECT name, concat (address||','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE
MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
B. SELECT name, address||','||city||','||country AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-
2000','DD-MON-RRRR')) <=36;
C. SELECT name, concat (address| | ','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE
TO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
D. SELECT name, concat (address| | ','| |city| |', ', country) AS
full_address,start_date,property_price, property_price*115/100FROM storesWHERE
MONTHS_BETWEEN (start_date, '01-JAN-2000') <=36;
Answer: A

QUESTION NO: 4
Evaluate the following SQL statements that are issued in the given order:
CREATE TABLE emp
(emp_no NUMBER(2) CONSTRAINT emp_emp_no_pk PRIMARY KEY,
ename VARCHAR2(15),
salary NUMBER (8,2),
mgr_no NUMBER(2) CONSTRAINT emp_mgr_fk REFERENCES emp(emp_no));
ALTER TABLE emp
DISABLE CONSTRAINT emp_emp_no_pk CASCADE;
ALTER TABLE emp
ENABLE CONSTRAINT emp_emp_no_pk;
What would be the status of the foreign key EMP_MGR_PK?
A. It would be automatically enabled and deferred.
B. It would be automatically enabled and immediate.
C. It would remain disabled and has to be enabled manually using the ALTER TABLE command.
D. It would remain disabled and can be enabled only by dropping the foreign key constraint and recreating it.
Answer: C

QUESTION NO: 5
View the Exhibit and examine the structure of the ORDER_ITEMS table. (Choose the best answer.)
You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?
A. SELECT order_idFROM order_itemsWHERE (unit_price*quantity) = (SELECT
MAX(unit_price*quantity)FROM order_itemsGROUP BY order_id)
B. SELECT order_idFROM order_itemsWHERE(unit_price*quantity)
MAX(unit_price*quantity)GROUP BY order_id);
C. SELECT order_idFROM order_itemsWHERE(unit_price*quantity) = (SELECT MAX
(SUM(unit_price*quantity)FROM order_items) GROUP BY order_id);
D. SELECT order_idFROM order_itemsGROUP BY order_idHAVING
SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity))FROM order_items GROUP BY order_id);
Answer: D

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1Z0-071 자격증덤프 - Oracle 1Z0-071 자격증덤프 - Oracle Database 12C SQL

PDF Questions & Answers

Exam Code: 1z0-071
Exam Name: Oracle Database 12c SQL
Updated: May 20, 2018
Total Q&As:162
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Exam Code: 1z0-071
Exam Name: Oracle Database 12c SQL
Updated: May 20, 2018
Total Q&As:162
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Exam Code: 1z0-071
Exam Name: Oracle Database 12c SQL
Updated: May 20, 2018
Total Q&As:162
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